bustr Posted August 8 Share Posted August 8 I have this code for software lines. *software,software ---- 0 ---- 0 ---- 0 ---- 0 ---- 0 ---- 0 -- A,.025,-.1,[CIRC1,ltypeshp.shx,x=-.04,s=.04],-.1,.125 I need a code for Fiber Optic lines. The two linetypes are shown below. The appearance is similar but slightly different. Does anyone have such a code that they could share with me? Quote Link to comment Share on other sites More sharing options...
bustr Posted August 8 Author Share Posted August 8 I struggled for an hour or so and came up with this. There is a small gap on the left side of the circle. Does anyone know how to close it? *FIBER_OPTIC, FIBER_OPTIC ----O----O----O----O----O- A, .2, .2,[CIRC1,ltypeshp.shx,x=.02,s=.04],-0.05, -0.05 fiber.dwg Quote Link to comment Share on other sites More sharing options...
BIGAL Posted August 9 Share Posted August 9 Maybe like this change values to suit. Note s=2.5 I think the circ1 is based on a 1 dia circle. The -5 gap = x offset. *JHOOK,JHOOKS ----O----O----O----O----O----O-- A,50,-5.0,[CIRC1,ltypeshp.shx,S=2.5,R=0.0,X=-5.0,Y=0.0] 1 Quote Link to comment Share on other sites More sharing options...
bustr Posted August 9 Author Share Posted August 9 Thanks. I'm off for the weekend but will give it a try Monday. Quote Link to comment Share on other sites More sharing options...
eldon Posted August 9 Share Posted August 9 16 hours ago, bustr said: I struggled for an hour or so and came up with this. There is a small gap on the left side of the circle. Does anyone know how to close it? *FIBER_OPTIC, FIBER_OPTIC ----O----O----O----O----O- A, .2, .2,[CIRC1,ltypeshp.shx,x=.02,s=.04],-0.05, -0.05 The short answer is that you have specified too much of a gap. The CIRC1 shape at a scale of 0.04 is 0.08 in diameter. So the space (negative distance) should be 0.08, and you have specified 0.05+0.05=0.10 which gives the 0.02 gap. I suspect you are just beginning to learn about linetype definitions, but to correct your code, I would amalgamate the two line sections and also the two space sections into one each. You do not need an x dimension because the insertion point of CIRC1 is at the left hand quadrant point. This would give the code line to be:- A, .4,[CIRC1,ltypeshp.shx,s=.04],-0.08 1 1 Quote Link to comment Share on other sites More sharing options...
bustr Posted August 13 Author Share Posted August 13 Thanks. That worked perfectly. Quote Link to comment Share on other sites More sharing options...
Recommended Posts
Join the conversation
You can post now and register later. If you have an account, sign in now to post with your account.
Note: Your post will require moderator approval before it will be visible.