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how to combine two list into one as follows?


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Posted

original lists:

(setq list1 '(a b c))

(setq list2 '(x y z))

 

results should be like this:

(setq list3 '('(a x) '(a y) '(a z) '(b x) '(b y) '(b z) '(c x) '(c y) '(c z))

Posted (edited)
(defun c:test ( / list1 list2 whatyouwant) 
  (setq list1 '("a" "b" "c"))
  (setq list2 '("x" "y" "z"))
  
  (defun ex:combinelist ( la lb / lal lbl lo indexa indexb ) 
    (setq lo '())
    (setq lal (length la))
    (setq lbl (length lb))
    (setq indexa 0)
    (repeat lal
      (setq indexb 0)
      (repeat lbl
        (setq lo (cons (list (nth indexa la) (nth indexb lb)) lo))
        (setq indexb (+ indexb 1))
      )
      (setq indexa (+ indexa 1))
    )
    (reverse lo)
  )
  (setq whatyouwant (ex:combinelist list1 list2))
  (princ whatyouwant)
  (princ)
)

 

Edited by exceed
Posted
(apply 'append (mapcar '(lambda ( x ) (mapcar '(lambda ( y ) (list x y)) list2)) list1))

 

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