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Posted

Can someone tell me please how to draw common external tangent of 2 circles such as below pic? Please teach me the technical drawing method of it. Thanks

 

 

tangent.PNG

Posted (edited)

1. Draw a circle with QP as diameter.
2. Set radius to 2 and draw arc to intersect this circle at T
3. Draw QT and extend to R
4. Draw PT
5. Set radius to PR and centered on T draw an arc at S
6. Draw RS

 

Do you want the theory as well?

 

 

Common Tangent construction.PNG

Edited by eldon
added to
Posted

That is a task for later. I am thinking about it.

 

It is so much easier with AutoCAD!

Posted (edited)

Assuming this is to be drawn with a compass and ruler (as the previous), here is how I would do it:
1 Draw a circle with AE as the diameter.
2. The crux of the problem is drawing arcs which have a radius of the difference between those of the circles. In the previous example, that was easy because the figure had dimensions. So set the radius as AG. Then centered on H draw the arc at J. Centered on E, put the radius as EJ, and draw the arcs ro give K and L.
3. Draw EK and EL and extend to circumference at D and F
4. Set radius at AD, then centered on K and L, draw arcs at B and C
5. Draw DB and FC

 

 

 

double external tangent construction-A.PNG

Edited by eldon
corrected
Posted

@eldon

 

In an earlier post you stated:

1. Draw a circle with QP as diameter.
2. Set radius to 2 and draw arc to intersect this circle at T
3. Draw QT and extend to R
4. Draw PT
5. Set radius to PR and centered on T draw an arc at S
6. Draw RS

 

I think step 5 should be 

5. Set radius to TP and draw arc cenetered at R to determine S.

Posted
34 minutes ago, lrm said:

@eldon

 

In an earlier post you stated:

1. Draw a circle with QP as diameter.
2. Set radius to 2 and draw arc to intersect this circle at T
3. Draw QT and extend to R
4. Draw PT
5. Set radius to PR and centered on T draw an arc at S
6. Draw RS

 

I think step 5 should be 

5. Set radius to TP and draw arc cenetered at R to determine S.

 

 

It is heartening to see others who can see the basic geometry - thank you.

 

I was trying to match diagonals of the right angled rectangle, but your solution matches the side length. Both solutions should give the same answer (I hope!)

Posted

Yes, you are correct, both methods will work!  I was fixated on the fact that since RT and SP  are parallel, RS = TP but of course, the diagonals of a rectangle will be equal as well.

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