FIND & REPLACE MLEADER TEXT

[Bill Tillman]

Here's the MLEADER text contents:

 

3"x3/4" RECTANGULAR

STEEL TUBE

 

I want to replace each instance of this with

 

3/4"x3" STEEL

FLAT BAR

 

This would seem cut and dry but apparently I don't have it right. If I do a FIND for the first string, it's on two lines as shown, it comes up with nothing. So how does one format a string in the FIND dialog window so it will select and change the desired text?

 

[mhupp]

Try  find and replace with this.

 

"3\"x3/4\" RECTANGULAR\\PSTEEL TUBE"

"3/4\"x3\" STEEL\\PFLAT BAR"

 

[Bill Tillman]

Trying to do this with the constant interruptions at my office is proving difficult. But I did try this and it came up null.

[mhupp]

¾" isn't the same as 3/4" that is whats causing the 0 finds.

¾ is one font char

3/4 is three font char's

 

search for this use \P for next line

3"x¾" RECTANGULAR\PSTEEL TUBE

 

--edit

to type ¾ hold alt and type 0190 on numbpad

 

 

Edited August 4, 2022 by mhupp

[Bill Tillman]

Ah, the old EXTENDED ASCII CHARACTER set. Cool, that works great with 3/4" but what if I have 7/8" or 23/32"  a number which is not an Extended Ascii character?

[BIGAL]

They should be part of text ?  IF they are not super / subscript .

 

 

Find and Mtext does not work. 

 

 

"\\A1;abc {\\H0.7x;\\S23/32;\\H1.42857x;\"}" so need a lisp maybe to amend string.
 

 

[Bill Tillman]

Yes, when the fractions auto-stack it creates a problem with FIND

[mhupp]

2 hours ago, Bill Tillman said:

Yes, when the fractions auto-stack it creates a problem with FIND

 

Best way to combat this is to double click the mtext and copy it. then add the /P to break them up by line.

[BIGAL]

Look for \S in string then ; so get "23/32" then further apart 23 32 and replace both. Then rebuild string. I dont have anything for task. 

 

In text if you have used extended character like ¼  you could look for a (chr x) but font style may vary. ps ¼ is (chr 188)

 

 

Edited August 5, 2022 by BIGAL