remove list item using a wildcard

[paulo]

How do I remove an item from a list using a wildcard query:

 

("big23" "large25" "superlarge26" "superlarge-27" "superlarge_28" and so on)

to

("big23" "large25" and so on), just removing the "superlarge..." parts)

 

Thanks in advance, guys.

[Tharwat]

Hi,

One way with mapcar & lambda functions.

(mapcar '(lambda (x)
           (if (wcmatch x "superlarge*")
             (substr x 12)
             x
           )
         )
        '("big23" "large25" "superlarge26" "superlarge-27" "superlarge_28")
)

 

[ziele_o2k]

@Tharwat I think that @paulo whant to remove item, not part of string:

Here are my solutions:

1. Use parse list function from this post
   And example of use:

   (pz:LST_Parse
       '("big23" "large25" "superlarge26" "superlarge-27" "superlarge_28")
       '(lambda (%) (wcmatch % "superla*"))
       t
   )

    

2. Or simply use vl-remove-if function

   (vl-remove-if 
       '(lambda (%) (wcmatch % "superla*")) 
       '("big23" "large25" "superlarge26" "superlarge-27" "superlarge_28")
   )

    

EDIT:

I notice today my forum rank: Rising Star - I love it

Edited September 24, 2018 by ziele_o2k

[Grrr]

Another variation for vl-remove-if behaviour:

(apply 'append
  (mapcar 
    '(lambda (x)
      (if (wcmatch x "superla*") (list x))
    )
    '("big23" "large25" "superlarge26" "superlarge-27" "superlarge_28")
  )
)

 

[paulo]

as usual, this forum is the way to go for the 'learners' like me. What more to say, another happy camper here, so thanks big time. Till the next time...