Jump to content

Lisp routine to round off text numbers in autocad (25.362~25.360) .. how to avoid 0 ?


Recommended Posts

Posted

This lisp routine is to set decimal digits after a comma in any integer to 2 digit for any set of entries even in term of text ,, how to avoid the appearance of 0 .. ( ex : 25.456 ~25.460 , 25.322~25.320 ) last 0 isn't preferable ..

 

; Program to add specific value to all the selected texts

(defun c:ROFF()

(setq selset(ssget (list (Cons 0 "TEXT"))))

(setq len(sslength selset))

(setq ctr 0)

(repeat len

(setq ent(Ssname selset ctr))

(setq ctr(1+ ctr))

(setq entl(entget ent))

(setq txtv(Atof (cdr (assoc 1 entl))))

(setq remval(- (fix (* txtv 1000)) (* 10 (fix (* txtv 100)))))

(setq fixedv(fix (* txtv 1000)))

(if (= remval 0) (setq fixn (+ fixedv 0)))

(if (= remval 1) (setq fixn (- fixedv 1)))

(if (= remval 2) (setq fixn (- fixedv 2)))

(if (= remval 3) (setq fixn (- fixedv 3)))

(if (= remval 4) (setq fixn (- fixedv 4)))

(if (= remval 5) (setq fixn (+ fixedv 5)))

(if (= remval 6) (setq fixn (+ fixedv 4)))

(if (= remval 7) (setq fixn (+ fixedv 3)))

(if (= remval 8) (setq fixn (+ fixedv 2)))

(if (= remval 9) (setq fixn (+ fixedv 1)))

(setq fixn(atof (rtos (/ fixn 1000.00) 2 )))

(setq sub(subst (Cons 1 (rtos fixn 2 )) (assoc 1 entl) entl))

(entmod sub)

(entupd ent)

)

(princ)

)

(princ "\nType \"ROFF\" at the command prompt") (princ)

Posted

emotion 8) should be replaced with

8 )
without space.
Posted

Look into DIMZIN sysvar -David

Posted

Here ya go...an old code i found.

Seemed to work with my single test on Acad 2011.

 

Just type NP, enter your precision and select the text/mtext.

 

;4-9-09
;Implements user specified precision on integers with or without text
;used getPrec by CAB
(defun c:NP (/ RtosPrec ss x Number Prec charlist n snumber numlist char strippednumber nnumber NewString)
(vl-load-com)
(setq RtosPrec (getint "Enter Precision to force on all Text and MText Integers:"))
(setq ss (ssget '((-4 . "<OR")(0 . "TEXT")(0 . "MTEXT")(-4 . "OR>"))))
(setq x 0)
(Repeat (sslength ss)
 (progn
  (setq Number (ssname ss x))
(defun getPrec (str)
   (if (vl-string-search "/" str)
     (setq str (vl-string-right-trim "0" (rtos (distof str) 2 ))
   )
   (if (vl-string-search "." str)
     (- (strlen str)(vl-string-search "." str) 1)
     0
   )
 )
(setq Prec (getprec (cdr (assoc 1 (entget Number)))))
(setq charlist (vl-string->list (cdr (assoc 1 (entget Number)))))
(setq n 0 snumber nil)
(setq numlist (list "0" "1" "2" "3" "4" "5" "6" "7" "8" "9"))
(repeat (length charlist)
 (setq char (chr (nth n charlist)))
 (if (member char numlist)
  (setq snumber (append snumber (list char)))
 );if
 (setq n (1+ n))
);repeat
(if snumber
(progn
(setq StrippedNumber 0)
(setq n (length snumber))
(setq char 0)
(repeat (- n prec)
 (setq StrippedNumber (+ StrippedNumber (* (atoi (nth char snumber))(expt 10 (1- (- n prec))))))
 (setq n (1- n)
        char (1+ char)
 );setq
);repeat
(setq n prec)
(setq char (length snumber))
(repeat prec
 (setq StrippedNumber (+ StrippedNumber (* (atoi (nth (1- char) snumber))(expt 0.1 n))))
 (setq n (1- n)
        char (1- char)
 );setq
);repeat
(setq snumber (rtos strippednumber 2 prec))
 (setq nnumber (rtos strippednumber 2 rtosprec))
(setq NewString
 (strcat
 (substr (cdr (assoc 1 (entget Number))) 1 (- (length (vl-string->list (cdr (assoc 1 (entget Number)))))(length (vl-string->list snumber))))
 nnumber
 )
)
(entmod (subst (cons 1 NewString)(assoc 1 (entget Number)) (entget Number)))
);progn
);if
);progn
(setq x (1+ x))
);repeat
);defun

Posted (edited)
emotion 8) should be replaced with without space.

Salama, please note that in advanced editor (Go advanced button at bottom of post input field, you will find a check box that will allow you to disable the automated smilies recognition in posts.

 

 

opt01.gif

 

Also, please consider using the Code tags instead of Quote ones when posting code excerpt; this will ensure keeping the formatting.

Edited by MSasu
Removed some formatting issues
Posted

Salama,

 

You could save a lot of "setq" use by using a "cond" statment see example below;

 

Modified Code;

(setq fixn
    (cond
        ((= remval 0)  (+ fixedv 0))
        ((= remval 1)  (- fixedv 1))
        ((= remval 2)  (- fixedv 2))
        ((= remval 3)  (- fixedv 3))
        ((= remval 4)  (- fixedv 4))
        ((= remval 5)  (+ fixedv 5))
        ((= remval 6)  (+ fixedv 4))
        ((= remval 7)  (+ fixedv 3))
        ((= remval   (+ fixedv 2))
        ((= remval 9)  (+ fixedv 1))
        )
    )

 

Your existing Code;

(if (= remval 0) (setq fixn (+ fixedv 0)))
(if (= remval 1) (setq fixn (- fixedv 1)))
(if (= remval 2) (setq fixn (- fixedv 2)))
(if (= remval 3) (setq fixn (- fixedv 3)))
(if (= remval 4) (setq fixn (- fixedv 4)))
(if (= remval 5) (setq fixn (+ fixedv 5)))
(if (= remval 6) (setq fixn (+ fixedv 4)))
(if (= remval 7) (setq fixn (+ fixedv 3)))
(if (= remval 8 (setq fixn (+ fixedv 2)))
(if (= remval 9) (setq fixn (+ fixedv 1))) 

Posted

or

(setq fixn (eval
	   (nth	remval
		'((+ fixedv 0)
		  (- fixedv 1)
		  (- fixedv 2)
		  (- fixedv 3)
		  (- fixedv 4)
		  (+ fixedv 5)
		  (+ fixedv 4)
		  (+ fixedv 3)
		  (+ fixedv 2)
		  (+ fixedv 1)
		 )
	   )
	 )
     )

or

(setq fixn (eval (cadr 
	   (assoc remval
		'((0 (+ fixedv 0))
		  (1 (- fixedv 1))
		  (2 (- fixedv 2))
		  (3 (- fixedv 3))
		  (4 (- fixedv 4))
		  (5 (+ fixedv 5))
		  (6 (+ fixedv 4))
		  (7 (+ fixedv 3))
		  (8 (+ fixedv 2))
		  (9 (+ fixedv 1))
		 )
	   )
	 )
     )
     )

 

you can even add

 

(if (and
     (< -1 fixedv 10)
     fixedv) (...))

Posted

Or:

(if (< remval 5)
   (setq fixn (- fixedv remval))
   (setq fixn (+ fixedv (- 10 remval)))
)

Posted
Or:

(if (< remval 5)
   (setq fixn (- fixedv remval))
   (setq fixn (+ fixedv (- 10 remval)));[b][color="blue"];<-- brilliant[/color][/b]
)

 

really? :lol: oh man, did you put a lot of thought on that one? or it only took you a minute to come up with that?

Posted
really? :lol: oh man, did you put a lot of thought on that one? or it only took you a minute to come up with that?

 

Thanks pBe - I spent some time trying to avoid the if statement, but the pattern for 5 and above was quite simple to spot as both numbers sum to 10 in each case :)

Join the conversation

You can post now and register later. If you have an account, sign in now to post with your account.
Note: Your post will require moderator approval before it will be visible.

Guest
Unfortunately, your content contains terms that we do not allow. Please edit your content to remove the highlighted words below.
Reply to this topic...

×   Pasted as rich text.   Restore formatting

  Only 75 emoji are allowed.

×   Your link has been automatically embedded.   Display as a link instead

×   Your previous content has been restored.   Clear editor

×   You cannot paste images directly. Upload or insert images from URL.

×
×
  • Create New...