JD Mather Posted December 27, 2012 Posted December 27, 2012 Delete the first yellow circle and trim the second yellow circle as shown below. Repeat this process with the cyan (little_r) arc as shown earlier in post #11. Attach the file here. Quote
JD Mather Posted December 27, 2012 Posted December 27, 2012 Draw line (shown green) from then end of the cyan arc to the center of the gear. Quote
JD Mather Posted December 27, 2012 Posted December 27, 2012 Rotate the vertical line -7.5° as shown. I think you can figure out the rest. (Join, Mirror, Trim, Array) there are 12 teeth in this design. Post back solution or further questions and I will attach the xls (can be set to any number over 12 teeth). Quote
spinecad Posted December 27, 2012 Author Posted December 27, 2012 Delete the first yellow circle and trim the second yellow circle as shown below.[ATTACH=CONFIG]39402[/ATTACH] Repeat this process with the cyan (little_r) arc as shown earlier in post #11. Attach the file here. The yellow circle shown on above is not similar with the yellow circle you shown on the #13. I can't continue because of this. Quote
spinecad Posted December 27, 2012 Author Posted December 27, 2012 Sorry, I think I skip the #20. Now I can continue. Quote
spinecad Posted December 27, 2012 Author Posted December 27, 2012 Another problem, I don't know how to make the cyan arc in #11. I can not continue. Quote
JD Mather Posted December 27, 2012 Posted December 27, 2012 make the cyan arc exactly like the yellow arc was made, but with a radius of .109167 (little_r) draw the circle with the center at the intersection of the red lines - just like the first yellow circle was drawn. draw second cyan circle where it intersects the red circle - just like was done with the second yellow circle. delete the first cyan circle trim the second cyan cirle If you still can't figure it out post back and I'll do step-by-step pictures Quote
spinecad Posted December 28, 2012 Author Posted December 28, 2012 (edited) make the cyan arc exactly like the yellow arc was made, but with a radius of .109167 (little_r)draw the circle with the center at the intersection of the red lines - just like the first yellow circle was drawn. draw second cyan circle where it intersects the red circle - just like was done with the second yellow circle. delete the first cyan circle trim the second cyan cirle If you still can't figure it out post back and I'll do step-by-step pictures Unlike the yellow circle/arc, the problem is I can not find the center of the cyan circle. The center of the yellow circle is known at the quadrant on the top of the white circle (D1.0000). Edited December 28, 2012 by spinecad Quote
spinecad Posted December 28, 2012 Author Posted December 28, 2012 Meanwhile, come take a look at my current work. I don't know whether it's correct or not. Geare.dwg Quote
JD Mather Posted December 29, 2012 Posted December 29, 2012 Unlike the yellow circle/arc, the problem is I can not find the center of the cyan circle. The center of the yellow circle is known at the quadrant on the top of the white circle (D1.0000). The center of the (original) cyan circle is at the same location. But as the radius is different - the new center intersection with the red circle is different. Both arcs are created in exactly the same way. Quote
spinecad Posted December 29, 2012 Author Posted December 29, 2012 The center of the (original) cyan circle is at the same location.But as the radius is different - the new center intersection with the red circle is different. Both arcs are created in exactly the same way. Doesn't really understand. Can you show me the step by a drawing? Quote
JD Mather Posted December 29, 2012 Posted December 29, 2012 The key is that the center of the second arcs (of each color) are at the intersection with the Base Circle (red). Quote
spinecad Posted December 29, 2012 Author Posted December 29, 2012 The key is that the center of the second arcs (of each color) are at the intersection with the Base Circle (red). [ATTACH=CONFIG]39421[/ATTACH] Now I understand. Quote
spinecad Posted December 29, 2012 Author Posted December 29, 2012 If this is a gear, how to draw its pinion? Quote
spinecad Posted December 30, 2012 Author Posted December 30, 2012 How to draw the tooth of these gears? gearandpinion.dwg Quote
JD Mather Posted December 30, 2012 Posted December 30, 2012 A pinion is the driving (powered) gear in a set while the gear is driven by the pinion. The driving gear is almost always smaller diameter (fewer teeth) than the driven gear. In the schematic you attached it doesn't make sense - looks like three gears mated with three different ratios - this can't work. Usually information is provided like # of teeth or ratio, pitch, pitch diameter. 2 of 3 variables are needed to calculate the 3rd. I think I asked at the outset whether inch or metric. It looks like you are interested in metric unit gears. A mating gear is modeled the same way as the first one but with different parameter values from the Excel spreadsheet calculations. The key is any two mating gears must have the same pitch (distance between teeth). Quote
spinecad Posted December 30, 2012 Author Posted December 30, 2012 A pinion is the driving (powered) gear in a set while the gear is driven by the pinion.The driving gear is almost always smaller diameter (fewer teeth) than the driven gear. In the schematic you attached it doesn't make sense - looks like three gears mated with three different ratios - this can't work. Usually information is provided like # of teeth or ratio, pitch, pitch diameter. 2 of 3 variables are needed to calculate the 3rd. I think I asked at the outset whether inch or metric. It looks like you are interested in metric unit gears. A mating gear is modeled the same way as the first one but with different parameter values from the Excel spreadsheet calculations. The key is any two mating gears must have the same pitch (distance between teeth). I really have no idea whether I can draw a three mating gears (or more) or not such as in my previous attached .dwg file (#36). I was said in inch, but metric is not a problem. How to draw the tooths of mating gear and pinion? Quote
JD Mather Posted December 30, 2012 Posted December 30, 2012 Let's assume the the 12 tooth gear is the pinion (since that is as few teeth as the Wellman's Odontograph method will work. How many teeth (or gear ratio, say 1:2) do you want on the driven gear. Let me know and I'll attach the *.xls and explain how to do the gear. (BTW - modern CAD programs like Autodesk Inventor will do all of this for you). Quote
spinecad Posted December 31, 2012 Author Posted December 31, 2012 Let's assume the the 12 tooth gear is the pinion (since that is as few teeth as the Wellman's Odontograph method will work.How many teeth (or gear ratio, say 1:2) do you want on the driven gear. Let me know and I'll attach the *.xls and explain how to do the gear. (BTW - modern CAD programs like Autodesk Inventor will do all of this for you). 12 teeths is OK. Quote
Recommended Posts
Join the conversation
You can post now and register later. If you have an account, sign in now to post with your account.
Note: Your post will require moderator approval before it will be visible.