paulmcz Posted December 8, 2012 Posted December 8, 2012 JD, step 3 is a solution for this problem only. It is a shortcut for this particular case. Revolving the profile in the case like this will work as well but it is limited to radius 5 too. Just imagine what shape you end up with if you revolve a profile with radius other than 5. Quote
paulmcz Posted December 8, 2012 Posted December 8, 2012 Revolved radius smaller and larger than 5, if we want the inner half-pipe intact: Quote
JD Mather Posted December 9, 2012 Posted December 9, 2012 JD, step 3 is a solution for this problem only... Isn't the outside radius supposed to be 7? That is what I read in the original post. Your "solution" doesn't look correct to me. Quote
paulmcz Posted December 9, 2012 Posted December 9, 2012 Outside radius of 7 on a pipe that has outside radius 5? I am trying to imagine how it should look like. To me, the only correct solution to this is that a sphere of a radius of 5 is where the 2 pipes join. Just like Remark shows in post #28. No other radius will fit there, if the two joining pipes have common center where they join. Don't you think? Quote
JD Mather Posted December 9, 2012 Posted December 9, 2012 I read the original drawing as outside radius 7 Inside radius 5 resulting wall thickness 2 The two solutions I posted both create spheres at the bends. Quote
paulmcz Posted December 9, 2012 Posted December 9, 2012 OK, I see it now. It does show 7 outside radius when you look closely. My solution and everything I suggested was meant for 5 outside radius of the pipe as well as the radius of the fillet. The procedure is the same though, whether it is 5, 7 or any other number. Sorry about that. Quote
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