Solve triangle with only two known sides

[The Buzzard]

Hello all,

 

Is there any way possible to get the angles of the right triangle below knowing only the distance of two sides?

 

I went through this once before, But I had a known distance and angle. This is a different situation.

 

Any help would be greatly appreciated.

The Buzzard

[MikeScott]

hypotenuse = 22.09

segment Y = 10.34

Solve for X

 

XX+YY=HH

 

XX + 106.9156 = 487.9681

 

XX = ?

 

Or.. do it in Autocad.. Draw a line that's 10.34, and then draw a circle whose centerpoint is at the end of that line, and whose radius is 22.09.

 

Then draw a line at 90-degrees from the other end of that line, and wherever it hit's the circle, that's your length.

 

 

Update: oops.. you wanted the angles.

 

Well, the total of the two missing angles should be 90 degrees when added together.. that much I know..

 

Here's the rest:

http://www.teacherschoice.com.au/maths_library/trigonometry/solve_trig_sss.htm

[fuccaro]

Yes, there is, and you have more ways.

1. Use the arccos function to calculate it

2. make an accurate construction in AutoCAD and put an angular dimension with a lot of decimals for higher precision.

 

once more: I can't type fast enough. MikeScott, you got me.

[eldon]

Or even graphically. Draw a line from 0,0 a distance 25 or so to the right, hozirontally. Then draw a circle of radius 22.09 centered on 0,0.

 

Offset the line 10.34 upwards. Draw a line perpendicular from the original line to the intersection of the offset line and the circle, and then back to 0,0.

 

Angles are there, as in picture

[JohnM]

this might help

http://www.clarku.edu/~djoyce/trig/right.html

[nukecad]

Ever heard of Pythagoras.

 

The square on the hypotenuse is equal to the sum of the squares on the other two sides.

[fuccaro]

  nukecad said:

Ever heard of Pythagoras.

But "The Buzzard" asked for an angle...

[Glen Smith]

Any High school geometry student should be able to tell you

SO CA TOA

Sine(angle) = opposite/hypotenuse

Cosine(angle) = adjacent/hypotenuse

Tangent(angle) = opposite/adjacent

 

so the angle = arcsine(opposite/hypotenuse)

arcsine(10.34/22.09)=27.91deg.

 

See Miss Sydney, despite your crappy teaching, I did learn something, and despite myself, retain it and apply it to the real world.

 

Glen

[eldon]

To labour the point, angles by formula

[alanjt]

Some Old Hippie: Sin(theta) = opp/hyp

Caught Another Hippie: Cos(theta) = adj/hyp

Tripping On Acid: Tan(theta) = opp/adj

[Freerefill]

  alanjt said:

Some Old Hippie: Sin(theta) = opp/hyp

Caught Another Hippie: Cos(theta) = adj/hyp

Tripping On Acid: Tan(theta) = opp/adj

 

Well I was going to say something about Wikipedia and the sine rule, but you win.

[alanjt]

  Freerefill said:

Well I was going to say something about Wikipedia and the sine rule, but you win.

In high school Trig. some girl stood up in class and said that aloud. I doubt I'll ever forget it.

[Glen Smith]

O Hell, Another Hour Of Algebra.

Sine Cosine Tangent

 

I know there are more of them, but SO CA TOA was the first that came to mind.

[nukecad]

  fuccaro said:

But "The Buzzard" asked for an angle...

 

Yes - but did say right angled triangle.

 

EDIT- He said 'right triangle' which in my book is the same thing.

[The Buzzard]

  Glen Smith said:

Any High school geometry student should be able to tell you

SO CA TOA

Sine(angle) = opposite/hypotenuse

Cosine(angle) = adjacent/hypotenuse

Tangent(angle) = opposite/adjacent

 

so the angle = arcsine(opposite/hypotenuse)

arcsine(10.34/22.09)=27.91deg.

 

See Miss Sydney, despite your crappy teaching, I did learn something, and despite myself, retain it and apply it to the real world.

 

Glen

 

To All,

Thanks for the help.

 

Glen,

 

Honestly, I appreciate your help, But please forgive me if my level of trig knowledge does not meet your standard. I am 60 and have not worked in the last 10 years. I have more pressing things worth remembering. I have not asked for for much from this site in the past and have given back a lot more. I do not have a need for this answer for myself, But to use it for a code to be posted for the forum for others to use. I do not mean to read between the lines, But when interpret your post, I get the impression you seem annoyed for my asking. It almost sounds insulting. I myself have gone that route without realizing it. I have been trying to keep in check and avoid these issues since.

 

All the same I thank you for your help as well.

The Buzzard

[Glen Smith]

Buzzard,

 

I sincerely apologize that my words and tone caused offense. I assure you that it was not my intent. Any and all irritation that I felt while posting was, or should have been anyway, directed at a high school Trig teacher who appeared (to me anyway) to use humiliation as her primary teaching tool.

 

The irony is that I acted in the same way with my flippant comment in my post. For that I apologize to you and the rest of the board.

 

Glen Smith

[The Buzzard]

  Glen Smith said:

Buzzard,

 

I sincerely apologize that my words and tone caused offense. I assure you that it was not my intent. Any and all irritation that I felt while posting was, or should have been anyway, directed at a high school Trig teacher who appeared (to me anyway) to use humiliation as her primary teaching tool.

 

The irony is that I acted in the same way with my flippant comment in my post. For that I apologize to you and the rest of the board.

 

Glen Smith

 

Glen,

 

It not a problem, I could not be sure if I was misinterpreting. I know I am not the sharpest knife in the draw, But that can come with age. Trust me when I tell you I am over it.

 

Take care

The Buzzard