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Posted

Hey everybody,

 

I´m trying to array a line inbetween a specific angle. But I continue to get what you see in the pic. I need perfectly spaced lines....How do I go about doing this?

 

Thanks

polar array.JPG

Posted

Math. You'll have to break the angle down into smaller increments. Use decimal degrees and a precision to four decimal places. That should be sufficient.

Posted

Why doesn´t cad do it, doesn´t seem that difficult...

Posted
Why doesn´t cad do it, doesn´t seem that difficult...

 

You'll have to pose that question to the programmers. I just tried to answer your question. There's probably a lisp routine somewhere that would did it for you. I did not look. Do us a favor and search for one. If you find a routine come back here and post it. Then we all be in your debt. :)

Posted

How do you know that your angle to fill is exactly 13° :cry:

 

If you only have the Angle precision at 0, then you will never know what the exact angle is. Instead of entering the angle, choose the option where you can pick the angle to fill, then it will divide the angle perfectly.

Posted

thanks eldon

Posted
Why doesn´t cad do it, doesn´t seem that difficult...

 

I thought it did...

 

ex.png

Posted
I thought it did...

 

[ATTACH]13666[/ATTACH]

From my test AutoCAD does it easily :huh::

array.png

Posted

I think that the basic problem here comes from dimensioning an angle to find out what the angle is, without changing the default settings (nearest degree).

 

In the picture, the red and blue lines are nearly one degree apart, but the dimension shows 13° for each. But if you change the units precision in the dimension style, the more accurate dimensions show what the angles really are.

 

So when using Polar array, always pick the angle if you have not set the lines to an exact angle.

AnglePrec.jpg

Posted
From my test AutoCAD does it easily :huh::

 

If neither line is at 0 or 180 degrees you will find that 2010 won't work as expected. The button to define the angle only allows one pick so the assumed angle of the other line is at 0.

 

This seems like a huge bug to me, we should be able to point to both lines and their intersection to define the angle.

Posted

Good point - I hadn't noticed that! :)

 

I wonder why it has been set up that way... even the getangle prompt in LISP allows two picks.. :huh:

Posted
If neither line is at 0 or 180 degrees you will find that 2010 won't work as expected. The button to define the angle only allows one pick so the assumed angle of the other line is at 0.

 

That is the way it has always been, and one suspects that not enough complaints have been registered with AutoCAD for them to make it work in a straightforward way with two picks :shock:

Posted

In lieu of more complex programming (and AutoCAD LT friendly, though I’m not sure if LT has the ‘CAL command) how about this as a two point option:

 

C^C^_select;\-array;p;;p;\\'cal;ang(@,end,end);;

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