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Showing content with the highest reputation on 07/09/2019 in all areas

  1. 1 point
  2. Ish I have updated the original code to include new layer. Tharwat did not know about Dynmode and initget handy to know. You never stop learning with Autocad.
    1 point
  3. So company policy is dont buy something that may improve company production and improve profit Hint search here triangulation.
    1 point
  4. Hi David Has something changed Cadtutor is running very slow it just changed maybe 2 days ago. I have tried Chrome and Edge.
    1 point
  5. Sounds like the manager is opening off screen. Take a look here for a possible solution: http://cadpanacea.com/wp/?p=692 Also, take a look here: https://knowledge.autodesk.com/support/autocad/troubleshooting/caas/sfdcarticles/sfdcarticles/Dialog-window-does-not-display-in-AutoCAD-and-the-program-appears-to-freeze.html
    1 point
  6. I meant to post this earlier, but the forum was unresponsive. Essentially this - (apply 'mapcar (cons '+ '((0 1) (1 2) (2 3)))) Is equivalent to: (mapcar '+ '(0 1) '(1 2) '(2 3)) Which is evaluated as: (list (+ 0 1 2) (+ 1 2 3))
    1 point
  7. Check this thread and this example from Lee should make it clear.
    1 point
  8. It's difficult to explain, and I'm sure I'll be corrected. Lst is a list of lists, so you cannot simply (mapcar '+ lst) or (apply '+ lst) as each sub entity is a list, not a number. So using your short example list from above it is the equivalent to (mapcar '+ (car lst) (cadr lst) (caddr lst)) or (mapcar '+ (nth 0 lst) (nth 1 lst) (nth 2 lst)). The (cons '+ lst) forms a new list in a format that mapcar can understand (+ (0 1) (1 2) (2 3)) where + is the function that mapcar needs to apply to the following sub lists list1 ....listn taking in turn the first element of each sub list followed by the second element, then the third until it reaches a point where one of the sublists is empty. Since mapcar itself is a function this can be applied to a list it understands. run these on the command line in Autocad: (setq lst '((0 1) (1 2) (2 3))) then (apply 'mapcar (cons '+ lst))) but try changing (cons '+ lst) to the following (cons '- lst) (cons '* lst) (cons 'min lst) (cons 'max lst) and watch what is returned alternatively (setq lst '(("A" "D") ("B" "E") ("C" "F"))) and (apply 'mapcar (cons 'strcat lst))
    1 point
  9. Yes ROW Right of way This is a better explaination. The correct coordinate is: 1420986.34, 783332.48 This is what the intersection should look like. The trim layer is the actual size of the sheet. I see that Penn Foster has changed the sheet size since I did mine. Read page 3 in the drawing set up instructions, it is easy to miss. If you still need more instruction, give the school a chance, we cant always be here to help all the time. I have to grade finals this week:unsure: so I am pretty busy.
    1 point
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